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The biggest mistake made in the sequence on unawareness is to insist on using utilities. What makes an utility an utility is how it interacts with probabilities to result in actions, namely, via expected utility maximization (EUM). There are several sets of principles from which EUM can be derived, and they come in two kinds: they either derive probabilities or take them for granted. The former has the issue that, as one of the background posts from the sequence says:
“The ‘degrees of belief’ studied in this post are not, e.g., our acceptable betting odds, or a probability distribution that (along with a utility function) rationalizes our preferences. Rather, they are our basic judgments of the plausibility of different possible outcomes.”
If we assume our actual epistemic state is more adequately represented as a set of probability distributions rather than a single (action-conditioned) probability distribution, then something went wrong with the arguments and I don’t see why their conclusions should be taken as action-guiding. Similarly, the later kind directly depends on assumptions that don’t hold, and therefore we also have no reason to accept their conclusions.
It’s not obviously correct that the solution is to stick to utilities anyway and then come up with some ad-hoc way of making them work with sets of probability distributions. Instead, a more principled approach is to take the theorems we used to justify EUM, replace the probabilities in their assumptions with sets of distributions, and then do the maths to find the proper generalization. In the special case where the sets contain a single distribution, this will hopefully still give us utilities and EUM, which the new theorem would link somehow to the behaviour in the general case. This would be analogous to how, without probabilities, EUM is equivalent to picking the/a highest precedence option according to some weak ordering, and this ordering imposes constraints on the set of utility functions that generalize it to the probabilistic case.
However, doing this with an arbitrary such theorem isn’t always clearly correct. E.g., the first VNM axiom is completeness: that given two lotteries, we either prefer one, the other, or we are indifferent between them; but if we are given two sets of lotteries instead, as the sequence insists, maybe they are just incomparable. We need some more basic set of assumptions that can work well with sets of distributions. Thankfully, those exist. You don’t need to read that post; the results presented here don’t depend on it. I was trying to adapt the theorem presented there, and in doing so and considering what happens in some simple cases, it immediately followed that there is a small set of (arguably) commonsensical properties that no decisionmaking procedure under unawareness (as formulated in the sequence) can simultaneously have.
Let’s assume that:
Then, the first two of the rationality principles that lead to the issue are as follows:
This already tells us how an agent should behave in the following case:
Let’s call P(A) the probability the agent gives to action A (so P(B) must be 1-P(A)).
Now, for each of the possibilities in the set, let’s swap the consequences of A and B. The epistemic state then is the following:
Since we swapped (the consequences of) A and B, the new P(A), let’s call it P’(A), must be equal to the old P(B), which was 1 minus the original P(A).
The epistemic state is a set, so we can swap the order in which we write the possibilities without affecting the set they represent, and therefore without changing the probabilities the agent gives to the actions, so that now we have:
Then, notice that this is exactly identical to the original scenario, so by consequentialism the action probabilities must also be identical. This means that P(A) = P’(A) = P(B) = 1 - P(A), and therefore P(A) = 0.5.
With a drawing, where:
we can see that this happens to be equivalent (in this case, and by coincidence) to maximizing the minimum probability of the event happening among the possibilities:
The third and last rationality principle, which I’ll call reflective stability, is that a rational agent, given the choice of behaving like they do behave, or some other way, chooses to behave like they do behave. That something roughly like this must be true of rational behaviour should hopefully be self-evident. I won’t make it precise in full generality, instead, I will just say what this looks like in the simplest possible case, which turns out to be enough for the proof:
Given any decision scenario (with a set of actions to choose from, which will have consequences), or uncertain decision scenario (a scenario will be chosen among some set according to some unconditional probability distribution), in which, before any of the randomness/unawareness is resolved, we choose (possibly randomly) between behaving like we would usually behave (when we get to the scenario), or producing some other action distributions (when we get to a scenario, conditioned on the scenario, and with probabilities given by the setup), so that from our point of view there is no other probability distribution over the two possible behaviours other than 100% our usual behaviour that results in uncertain/unaware consequences identical to those that would result from selecting our usual behaviour (again, with probability 100%), we should choose to behave that way (with probability 100%).
For example, say we have the same setup as before, but instead of deciding between A and B directly, the agent’s choice is between selecting either some other agent or themselves to make the decision. I will call (arbitrarily since it is a set) 1 and 2 the two possible conditional distributions under consideration (same as in the previous setup). Then, assume the other agent chooses action A with probability 75%. This is depicted in the drawing below:
If the other agent is chosen, their epistemic state doesn’t matter, only that they choose A with probability 75%. This results, under each of the possible conditional distributions in:
If our (rational) agent is chosen, their epistemic state is restricted to that of the initial setup and, as concluded before, they will select A with probability 50%, which results, under each of the possibilities in:
By consequentialism, the epistemic state (or at least the part they can act on) of the agent when choosing between the other agent and themselves is, for each possibility in the set (keeping in mind the actions are not actually named “other agent” and “same agent” or anything like that as part of the state, they are just the first and second actions):
Given this information, the reflective stability principle says they must choose themselves (second action) with probability 100%.
But then consider the case where, after the agent is chosen, a coin is flipped. If it lands heads (50% chance) the agent will be put in the original scenario, but if it lands tails (50% chance), they will be put in a scenario where, regardless of what they choose, in the two possibilities from the set, respectively (given arbitrary numbers as before):
The choice of agent is now between our agent and a new agent that will choose A with probability 0% (will choose B). This looks as follows:
Again, given this information the reflective stability principle says they must choose themselves with probability 100%. However, notice the epistemic state the agent is in when choosing between the agents. The possibilities are:
By consequentialism as far as the agent is concerned, this is the exactly same epistemic state as that in the previous diagram! (again the “our agent” and “some other agent” labels are not part of the epistemic state) But then they should do what they did before and choose the second action, which now corresponds to the new agent, not themselves, so we have a contradiction.
Reality is not forced to give us a proper way to behave under arbitrary epistemic states, and the situation could be worse than just being unaware: maybe all possible behaviours are wrong. I’m very much not saying this is necessarily the case: maybe it turns out that the right thing to do is to use some sort of equivalence classes when defining reflective stability, or maybe, just like generalizations of probability should probably have epistemic origins instead of being derived from principles of rational action, generalizations of (or alternatives to) utility functions should have their origin in the structure of minds instead of in coherence theorems (the theorems don’t tell us what the concrete utility function should be, after all), or maybe it just doesn't make sense to be unaware of a bit. In any case, that’s all I have for now.
Perhaps I'm missing something, but could you explain how this is justifiable? In order to keep it straight in my head, I gave an example to your formula and assumed that, say, action A is letting baby Hitler live, action B is killing baby Hitler, and the "event" consequences are the holocaust. In your first example then, where action A could represent letting baby Hitler live, you are 100% guaranteeing the holocaust (for sake of argument), meanwhile action B could represent killing baby Hitler, thus giving 0% chance of the holocaust (for sake of argument). But I guess I'm not understanding how you can switch these consequences, and assume that somehow, maybe, killing baby Hitler would actually cause the holocaust, and letting him live would prevent it? I guess I just don't see how the 100%/0% formulation can hold if your argument for allowing the swapping is the unawareness/uncertainty itself. If letting baby Hitler live isn't a 100% guarantee of the holocaust, then how can we posit it? And if it is, then how could you ever switch that percentage to 0%?
Again, I may be missing something, but to me this seems like an equivocation. Does A actually behave exactly like B, or are you just swapping the definition of A and B, and saying that maybe killing baby Hitler could be A, and letting him live B, and therefore the consequences are identical? Sure, it's true, the naming choices of A and B are arbitrary, but the swapping of consequences, and the set of possible outcomes doesn't intuitively seem to be. At least, not to me. Maybe I'm missing something?
Action A is whatever action is in the first position, and action B in the second, in whatever list of actions we have. When I say, "let’s swap the consequences of A and B", that's equivalent to saying "let's consider a second scenario, that need not have anything else to do with the first one, except that the consequences of the action in the new first entry are identical to those of the second entry of the original scenario (and vice versa), and the number of actions and sets of outcomes stay the same". We are considering consequentialists, and, by definition, as far as their decisionmaking procedure is concerned, two scenarios where the actions in each entry have identical (uncertain/unaware) consequences are the same scenario. Though, if it helps, you can imagine we have two buttons, labelled A and B, so that swapping their consequences can be achieved by swapping whatever their cables are connected to.
Thank you! That does answer my question, I was assuming it was the same or similar scenario.