This is a linkpost for Von Neumann–Morgenstern utility theorem, which shows that one accepts 4 premises if and only if one maximises expected utility. In my mind, all the 4 premises are self-evident. So I do not see how one can reject maximising expected utility in principle. Relatedly, I think the Repugnant Conclusion follows from 3 self-evident premises.
In 1947, John von Neumann and Oskar Morgenstern proved that any individual whose preferences satisfied four axioms [premises] has a utility function, where such an individual's preferences can be represented on an interval scale [which "allows for defining the degree of difference between measurements"] and the individual will always prefer actions that maximize expected utility.[1] That is, they proved that an agent is (VNM-)rational [has preferences satisfying the 4 axioms] if and only if there exists a real-valued function u defined by possible outcomes such that every preference of the agent is characterized by maximizing the expected value of u, which can then be defined as the agent's VNM-utility (it is unique up to affine transformations i.e. adding a constant and multiplying by a positive scalar). No claim is made that the agent has a "conscious desire" to maximize u, only that u exists.
[...]
Completeness assumes that an individual has well defined preferences:
Axiom 1 (Completeness) For any lotteries and , either or .
(the individual must express some preference or indifference[4]). Note that this implies reflexivity.
Transitivity assumes that preferences are consistent across any three options:
Axiom 2 (Transitivity) If and , then .
Continuity assumes that there is a "tipping point" between being better than and worse than a given middle option:
Axiom 3 (Continuity): If , then there exists a probability such that
where the notation on the left side refers to a situation in which is received with probability and is received with probability .
[...]
Independence assumes that a preference holds independently of the probability of another outcome.
Axiom 4 (Independence): For any and (with the "irrelevant" part of the lottery underlined):
if and only if
In other words, the probabilities involving cancel out and don't affect our decision, because the probability of is the same in both lotteries.
Assume your utility function u is unbounded from above. Pick outcomes x1,x2,... such that u(xn)≥2n. Let your lottery X be xn with probability 1/2n. Note that ∑∞n=11/2n=1, so the probabilities sum to 1.
Then this lottery has infinite expected utility:
E[u(X)]=∞∑n=112nu(xn)≥∞∑n=112n2n=∞∑n=11=∞.Now, consider any two other lotteries A and B with finite expected utility, such that A≺B≺X. There's no way to mix A and X probabilistically to be equivalent to B, because
E[u(pA+(1−p)X)]=pE[u(A)]+(1−p)E[u(X)]=pE[u(A)]+∞=∞>E[u(B)],whenever p<1. For p=1, E[pA+(1−p)X]=E[u(A)]<E[u(B)].
So Continuity is violated.